Arectangular patio has an area of 91 fl. the length is 6 feet longer than the width. find the dimensions of the patio area solve by completing the square, find the width and the length interms of w. write an equation for the total area find b/2 find the dimensions.

Total area equation = tex]w(w+6)=91[/tex]

b/2 = 3

Dimensions of the patio: width = 7 feet, length = 13 feet

Step-by-step explanation:

The area of a rectangle is given the formula:

where

is the width

is the length

We know from our problem that the area of the patio is 91 square feet, so . We also know that the length is 6 feet longer then the width, so .

Replacing values in our area equation

Expanding the left side:

Remember that to complete the square we need to add half the coefficient of the linear term squared. The lineal term is , so its coefficient is 6. Now, half its coefficient or . Finally, .

To complete the square we need to add 9 to both sides of the equation:

Notice that the left side is a perfect square trinomial (both and 9 are perfect squares), so we can express it as:

Now that we completed the square, we can solve our equation

- Take square root to both sides

- Subtract 3 from both results

Since length cannot be negative, is the solution of our equation.

We now know that the width of our rectangular patio is 7 feet, so we can find its length:

We can conclude that half the coefficient of the width is , the width of the patio is 7 feet, and its length is 13 feet.

the answer is 0.3175 hope that you ^w^

also you might actually want to put this picture up if you want people to solve it luckily i remember this question

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation: