If f(x) = –2x+8 and g(x) = square root of x+7, what is (fºg)(2)

(fog)(2)=2

Step-by-step explanation:

Given

f(x)= -2x+8

and

g(x)= √(x+7)

For finding (fog)(2), we have to find (fog)(x) first

In order to find (fog)(x) we will put the value of g(x) in f(x) in place of x.

(fog)(x)= -2g(x)+8

Putting the value of g(x)  

(fog)(x)= -2√(x+7)+8

We have to find (fog)(2), so we have to put at the place of x in the composition

(fog)(x)= -2√(2+7)+8

(fog)(x)= -2√9+8

= -2(3)+8

= -6+8

=2

So,

(fog)(2)=2   ..

solution:

→c= a b , that is product of a and b is possible only when when a is m × n matrix and b is n × p matrix.

that is, number of columns of a= number of rows of b.

so, size of matrix , c= a b is , if a = (m × n)matrix

b= (n × p)matrix

then a b = [ (m × n)matrix] ×[   (n × p)matrix ]

→→c= a b= [m × p ] matrix

→→size of product a b will be equal to = number of rows of a × number of columns of b

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step-by-step explanation: