Write a quadratic variation equation if g(x) varies directly with x2, and g(x) = 98 when x = 7

g(x)=2x^2

Step-by-step explanation:

g(x)=kx^2

98=k(7)^2

or 98=49k

k=2

so g(x)=2x^2

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.