Plz 10000000 points///given: p: two linear functions have different coefficients of x. q: the graphs of two functions intersect at exactly one point. which statement is logically equivalent to q → p? if two linear functions have different coefficients of x, then the graphs of the two functions intersect at exactly one point. if two linear functions have the same coefficients of x, then the graphs of the two linear functions do not intersect at exactly one point. if the graphs of two functions do not intersect at exactly one point, then the two linear functions have the same coefficients of x. if the graphs of two functions intersect at exactly one point, then the two linear functions have the same coefficients of x.

area of part 1:

a1=base*height/2=(8+2)*(8-2-2-1)/2=10*3/2=15 ft^2

area of part 2:

a2=length*width=(8+2)*1=10 ft2

area of part 3:

a3=length*width=8*2=16 ft2

total shaded area : a1+a2+a3=41 ft2

total area of the reactangle : a=16*8=128 ft2

total area of the nonshaded region : 128-41=87 ft2

vbbv

step-by-step explanation:

answer is the third choice:

3x^5+4x^4+x^3+2x^2-10x-7=0

step-by-step explanation:

the correct option is 2.

step-by-step explanation:

according to the given information triangle abc is a right angle triangle with right angle at a. segment ab is 5 and segment ac is 7. point d is on segment bc and angles adb and adc are right angles.

it is given that triangles abd, cad, and cba are similar.

two triangles are similar if their corresponding sides are proportional.

in triangle cba, using pythagoras theorem

                      )

triangle abd and cba are similar,

                            (2)

triangle cad and cba are similar,

                      )

using (1), (2) and (3), we get

hence proved.

therefore option 2 is correct.