Aspinner is divided into four equal sections that are numbered 2, 3, 4, and 9. the spinner is spun twice. how many outcomes have a product less than 20 and contain at least one even number?

7

Step-by-step explanation:

Considered that the spinner is spun twice, we have 16 different combinations:

2 2

2 3

2 4

2 9

3 2

3 3

3 4

3 9

4 2

4 3

4 4

4 9

9 2

9 3

9 4

9 9

I have written in bold the combinations that contain at least one even number: there are 12 of them.

Now we have to check the product of each of these combinations:

2 x 3 = 6

2 x 9 = 18

3 x 2 = 6

3 x 3 = 9

3 x 4 = 12

3 x 9 = 27

4 x 3 = 12

4 x 9 = 36

9 x 2 = 18

9 x 3 = 27

9 x 4 = 36

9 x 9 = 81

Here I have written in bold the combinations that have a product less than 20: there are 7 of them.

So, 7 out of 16 outcomes have a product less than 20 and contain at least one even number.

answerthe vertex form

step-by-step explanation:

hello from mrbilldoesmath!

answer:

25x^2 + 90x + 84

discussion:

mn(x) = m(n(x)) = m( 5x + 9) =

(5x + 9)^2 + 3 =>

25x^2 + 90x + 9^2 + 3 =

25x^2 + 90x + 84                 (as 9^2 = 9*9 = 81)

which is the second choice

regards,  

mrb

p.s.   i'll be on vacation from friday, dec 22 to jan 2, 2019. have a great new year!