Miriam reduced a square photo by cutting 3 inches away from the length and the width so it will fit in her photo album. the area of the reduced photo is 64 square inches. in the equation (x – 3)2 = 64, x represents the side measure of the original photo. what were the dimensions of the original photo? 11 inches by 11 inches 5 inches by 5 inches 3 + inches by 3 + inches 3 inches by 3 inches

11 inches by 11 inches

Step-by-step explanation:

The dimensions of the original photo were 11 inches by 11 inches.

We are informed that the area of the reduced photo is 64 square inches and that In the equation (x – 3)^2 = 64, x represents the side measure of the original photo.

In order to solve for x, we shall first take square roots on both sides of the equation;

The square root of (x – 3)^2 is simply (x - 3).

The square root of 64 is ±8 but we ignore -8 since the dimensions of any figure must be positive.

Therefore, we have the following equation;

x - 3 = 8

x = 8 + 3

x = 11

step-by-step explanation:

36/60

36/2=18

60/2=30

18/30

18/3=6

30/3=10

6/10

6/2=3

10/2=5

your final answer would be 3/5 of an

hope this !