Consider the series 3 + 5 + 7 + 9 + + 2n + 1. write sk and sk+1 a. sk=k(2k); sk+1=(k+1)(k+2) b. sk=k(k+2); sk+1=(k+1)(k+2) c. sk=k(2k); sk+1=(k+1)(k+3) d. sk=k(k+2); sk+1=(k+1)(k+3)

4y - 6 + y^2 - 9 = y^2 + 4y - 15

y^2 term

terms

- terms

total of 3 terms when simplified

step-by-step explanation:

(a) x intercepts: -6 and 2

you can obtain these by solving the equation 0=x^2 +4x-12 using your favorite quadratic formula. but it is easy to verify -6 and 2 indeed satisfy this equation.

(b) y intercept: -12

this is obtained by setting x=0: 0^2+4*0-12 = -12

(c) the minimum value is: -16 (this is the vertex)

you can get the vertex by rewriting the equation into the form:

there is no global or local maximum as the function goes to infinity, so only in the limit sense: +infinity.