Plsss a football quarterback goes for a two-point conversion when the ball is within 10 yards of the end zone. during the game, he has two opportunities for a two-point conversion. he misses the first attempt 50% of the time. when he misses the first attempt, he misses the second attempt 15% of the time. what is the probability of missing both two-point conversion attempts?

The probability of missing both two-point conversion attempts is 7.5%

Step-by-step explanation:

We are informed that the probability of missing the first attempt is 50% of the time. Furthermore, the probability of missing on the second attempt given that he missed the first attempt is 15% of the time

Now,the probability of missing on both the two-point conversion attempts will simply be given by the product of these two probabilities since the events are independent;

50%*15% = 0.5 * 0.15 = 7.5%

Therefore, the probability of missing both two-point conversion attempts is 7.5%

hello :

70y^8 + 30y^6 = 2 ( 35 y^8 + 15y^6)

the lenght is : 35 y^8

the width is : 15y^6

8/k

step-by-step explanation: