The diagonals of quadrilateral abcd intersect at e (2,5). abcd has vertices at a (3,7) and b (3,6). what must be the coordinates of upper c and upper d to ensure that abcd is a parallelogram?

C(1,3) and D(1,4).

Step-by-step explanation:

The given quadrilateral ABCD has vertices at A (3,7) and B (3,6). The diagonals of  this quadrilateral ABCD intersect at E (2,5).

Recall that, the diagonals of a parallelogram bisects each other.

This means that; E(2,5) is the midpoint of each diagonal.

Let C and D have coordinates C(m,n) and D(s,t)

Using the midpoint rule:

The midpoint of AC is

This implies that;

The midpoint of BD is

This implies that;

Therefore the coordinates of C are (1,3) and D(1,4).

f(x) is the value of the function. b is the value of the function when x equals zero or the y-coordinate of the point where the line crosses the y-axis in the coordinate plane.

step-by-step explanation:

hope this !

y = i/2 xtnop + (3i/2 tnop+ 1)

step-by-step explanation:

the picture is the step by step explanation.