The line that passes through the points (-5,-6) and (-3,2) and the line with equation y=x-4 intersect at what point?

(-6,-10)

Step-by-step explanation:

Let’s say that A is (-5,-6) and B is (-3,2). The slope of AB is (-6-2)/(-5+3)=(-8)/(-2)=4

The equation of AB is:

y-2=4(x+3)

y=4x+14

The lines intersect in:

4x+14=x-4

3x=-18

x=-6

(-6,-10)

answer: (c) m∠qpo + (2x + 16)° = 180°

step-by-step explanation:

the opposite angles of a quadrilateral are supplementary.

so, ∠o + ∠q = 180°   and   ∠p + ∠r = 180°

since ∠r = 2x + 16°, we can use substitution as follows:

∠p + ∠r = 180°

∠p + (2x + 16)° = 180°

i need a diagram

step-by-step explanation:

no