Type the correct answer in each box. use numerals instead of words. if necessary, use / for the fraction bar(s). a six-sided die of unknown bias is rolled 20 times, and the number 3 comes up 6 times. in the next three rounds (the die is rolled 20 times in each round), the number 3 comes up 6 times, 5 times, and 7 times. the experimental probability of rolling a 3 is %, which is approximately % more than its theoretical probability. (round off your answers to the nearest integer.)

The experimental probability of getting a 3 on a die is 30% which is approximately 13% more than its theoretical probability (17%).

Step-by-step explanation:

Theoretical probability of number 3 on a die:

Total no. of possibilities = 6

Probability of getting a 3 on a die each time it is rolled = 1/6

= 0.16667

= 17%

Experimental probability of number 3 on a die:

Total no. of rounds = 4

Rolls each round = 20

no. of 3s in round 1 = 6

no. of 3s in round 2 = 6

no. of 3s in round 3 = 5

no. of 3s in round 4 = 7

Total rolls = 20*4 = 80

no. of times 3 comes up = 6+6+5+7 = 24

Experimental probability of getting a 3 on a die

each time it is rolled = no. of 3s/total rolls

= 24/80

= 0.3

= 30%

Difference = 30% - 17% = 13%

Experimental probability of getting a 3 on a die is 30% which is approximately 13% more than its theoretical probability (17%).

deez nu tz

step-by-step explanation:

answer: 75°

step-by-step explanation:

∠esk is the supplement of ∠edk, so is 100°. ∠esd = 1/2·arc ed, so is 25°.

since ∠esk = ∠esd + ∠dsk

you have 100° = 25° + ∠dsk . .

fill in known values 75° = ∠dsk . . . . .

subtract 25°

step-by-step explanation: