Afraction reduces to 36. if its denominator is 6x^5, what it's its numerator?

Step-by-step explanation:

We know that the denominator of the fraction is

The numerator is unknown and the result of reducing the fraction is 36.

If we call N the numerator then:

Solve the equation for N

Finally, the numerator is:

The numerator of the fraction is 216x^5

Step-by-step explanation:

* Lets explain how to solve the problem

- There is a fraction

- Its denominator is 6x^5

- The numerator is missing

- The simplest form for the answer is 36

* Lets change the information to calculation

- Assume the numerator is n

∴ n/6x^5 = 36

- There is no x in the answer

∴ The numerator must has x^5 to cancel the x^5 in the denominator

- Find the number which divided by 6 and the answer will be 36

∵ missing number/6 = 36 ⇒ by using cross multiplication

∴ missing number = 36 × 6 = 216

- Then n consists of 216 and x^5

∴ n = 216 x^5

∴ The numerator is 216x^5

- Lets check the answer

∵ The fraction is 216x^5/6x^5 ⇒ reduce the fraction

∵ 216/6 = 36

∵ x^5/x^5 = 1

∴ 216x^5/6x^5 = 36

∴ The numerator of the fraction is 216x^5

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