Mrs. r is pregnant and very worried that the child will have beta-thalassemia. what is the probability that the child will have beta-thalassemia major? what is the probability that the child will have no trace of the disease? choose the correct answer. choose the correct answer. 50% chance of having beta-thalassemia major; 0% chance of being disease-free 75% chance of having beta-thalassemia major; 25% chance of being disease-free 25% chance of having beta-thalassemia major; 25% chance of being disease-free 0% chance of having beta-thalassemia major; 50% chance of being disease-free 50% chance of having beta-thalassemia major; 50% chance of being disease-free

lockers 1, 4, 9, 16, 25, 40, and 49 are open

i ran through it by the other answer is wrong

the simplified form is

step-by-step explanation:

we want to simplify the expression,

let us change the middle bar to a normal division sign to obtain,

we multiply the first fraction by the reciprocal of the second fraction to obtain,

we factor to obtain,

we cancel the common factors to get,

we simplify to get,

the correct answer is b

ending amount = beginning amount / (2^n)

where "n" = number of half-lives (or elapsed time / half-life)

ending amount = 50 mg / (2 ^10 / 5.3)

ending amount = 50 mg / (2 ^ 1.8867924528)

ending amount = 50 m / 3.6981210597

ending amount = 13.5203794557 mg

or about 13.5 mg remain

source:  

the answer for the question that you are asking is 4