With these questions, i don't understand them!

• arc PS = 40°

• arc UV = 24°

Step-by-step explanation:

There are relationships between the arcs intercepted by secant lines and the angle the secant lines make with each other. In these problems, you are expected to make use of these relationships, along with others you have learned about triangles.

The relationships are basically these:

• when the secants intersect inside the circle, the angle between them is half the sum of the intercepted arcs.

• when the secants intersect outside the circle, the angle between them is half the difference of the intercepted arcs.

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First problem:

The angle between the secants QS and PR is shown to be 50°. Intercepted arc QR is shown to be 60°. You are asked to find the other intercepted arc, PS. Based on the above, we know ...

∠POS = (1/2)(arc PS + arc QR)

50° = (1/2)(arc PS + 60°)

Multiplying by 2, we get ...

100° = arc PS + 60°

Subtracting 60°, gives ...

40° = arc PS

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Second problem:

We need to name a couple of points so we can describe more clearly what is going on. Call the point on arc PS where line QT intersects it point R. Call the point where line QT crosses line SU point X. (Point X is the vertex of the 99° angle.)

The relations described above tell us ...

angle W = (1/2)(arc PS - arc UV)

In this equation, we only know the value of arc PS = arc PR + arc RS = 20° + 94° = 114°.

But, we know two of the angles in triangle QWX. They are angle Q = 36° and angle X = 99°. Then angle W must be ...

angle W = 180° -36° -99° = 45°

Now, we can finish the above equation involving arc UV:

45° = (1/2)(arc PS - arc UV) . . . . . put the values we know in the secant relation

90° = 114° -arc UV

arc UV = 114° -90° = 24° . . . . . . . .solve for arc UV

answer for #1 is c

answer for #2 is d

can i get brainliest

the results from a pre-test for students for the year 2000 and the year 2010 are illustrated in the box plot. what do these results tell us about how students performed on the 29 question pre-test for the two years?

if we compare only the lowest and highest scores between the two years, we might conclude that the students in 2010 did better than the students in 2010. this conclusion seems to follow since the lowest score of 8 in 2010 is greater in value than the lowest score of 6 in 2000. also, the highest score of 28 in 2010 is greater in value than the highest score of 27 in 2000.

but the box portion of the illustration gives us more detailed information. the middle bar in each box shows us that the median score of 20 in 2000 is greater in value than the median score of 17 in 2010. further, we note that the box and whiskers divide the illustration into four pieces. each of these four pieces represents the same portion of students. so, the upper half of the students in 2000 scored in the same score range as the upper one-fourth of the students in 2010, see the illustration at a score of 20.

by considering the upper one-fourth, upper half, and upper three-fourths instead of just the lowest and highest scores, we would conclude that the students as a whole did much better in 2000 than in 2010. we would conclude that as a whole the students in 2010 are less prepared than the students in 2000.

in this section, we discuss box-and-whisker plots and the five key values used in constructing a box-and-whisker plot. the key values are called a five-number summary, which consists of the minimum, first quartile, median, third quartile, and maximum.

step-by-step explanation: