I’m not sure how to solve this. show how you solve this problem, you.

Pretend that H is the midpoint of AB, connect O and H

=> OH is the median of ΔOAB

Since we know that OA = OB => ΔOAB is an isosceles triangle

=> OH is also the height of ΔOAB

=> ∠OBA = ∠OAB = (180° - ∠AOB)/2 = (180° - 120°)/2 = 60°/2 = 30°

Now look at ΔOHB (that you create by connecting O and H)

We have:

cos30° = BH/OB

=> BH = cos30° · OB = √3/2 · x = (√3 x)/2

Because we have H as the midpoint of AB, we know that:

AB = 2 · BH = 2 · (√3 x)/2 = √3 x

So the answer is B

asdsad

step-by-step explanation:

step-by-step explanation:

at each of the parallel lines adjacent angles are supplementary. the angles have special names identifying their positions with respect to the parallel lines and transversal. they are corresponding angles, alternate interior angles, or alternate exterior angles. an angles is congruent to its matched angle.