(3q) find the amplitude and period of f(t)= -tan.0t

It has no amplitud and the period is 5pi/2

Step-by-step explanation:

Given a function of the following type:

f(t) = AtanB(t + C)

The function has no amplitud, given that it doesn't have maximum or minimum value.  And the period is given by: pi/B

In this case, we have f(t)= -tan0.4t. Then:

B = 0.4

⇒ Period = pi/0.4 = 5pi/2

Therefore, the answer is: It has no amplitud and the period is 5pi/2

linear pair postulates