Agame called "small poker" is played with a standard deck of 52 playing cards (no jokers). in "small poker," each player is dealt four cards (called a "hand"). (a) how many four-card hands are possible?(b) how many four-card hands consisting of four hearts are possible?(c) how many four-card hands consisting of four aces are possible? . (d) how many four-card hands consisting of two pairs are possible? hint: two pairs cannot create a "four of a kind" combination

a. From 52 total cards, you're drawing 4:

b. There are 13 hearts in the deck, and you want all 4 to be drawn from that pool. From the remaining 39, you are drawing nothing:

c. Similar to (b), but there are only 4 aces in the deck, and you don't care about the remaining 48 cards:

d. There are 13 ranks (ace, 2, 3, ..., 10, jack, queen, king) from which you want to draw 2. For each given rank, there are 4 possible suits, and a two of a kind consists of drawing 2 cards of the same rank, regardless of suit. Once you have two pairs, you ignore the remaining.

That is, there are ways of getting two pairs if the two ranks are fixed. Then you multiply this by , the number of ways you can get two different ranks.

you going to fail stop

step-by-step explanation:

area of part 1:

a1=base*height/2=(8+2)*(8-2-2-1)/2=10*3/2=15 ft^2

area of part 2:

a2=length*width=(8+2)*1=10 ft2

area of part 3:

a3=length*width=8*2=16 ft2

total shaded area : a1+a2+a3=41 ft2

total area of the reactangle : a=16*8=128 ft2

total area of the nonshaded region : 128-41=87 ft2