Mathematics, 27.06.2019 16:00 ximena68

Find an equation of the line passing through the pair of points. write the equation in the form ax + by = c. left parenthesis 4 comma 7 right parenthesis and left parenthesis 3 comma 4 right parenthesis(4,7) and (3,4) the equation of the line in the form ax+by=c is

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Answer from: mazielynn84

The equation of the line in the form of Ax + By = C is 3x - y = 7.

Given that,

The equation of the line in the form Ax +By = C,

Which passes through the points (4, 3) and (3,4).

We have to determine,

The equation of the line.

According to the question,

The equation of the line in the form Ax +By = C,

The co-ordinate passes through the points (4, 3) and (3,4).

To determine the equation of the line following all the steps given below.

Step1; The slope of the two points can be written as,

$m = \dfrac{y_2-y_1}{x_2-x_2}\\\\m = \dfrac{4-7}{3-4}\\\\m = \dfrac{-3}{-1}\\\\m = 3$

The slope of the line is 3.

Step2; The y-intercept of the line,

$y = mx + c\\\\7= 3 \times 4 + c\\\\7 = 12+ c\\\\c = 7-12\\\\c = -5$

The y-intercept of the line is -7.

Step3; The equation for the line is,

$y = mx + c \\\\y = 3x-7$

Step4; The equation can be written as standard form,

$y = 3x - 7\\\\3x -y = 7$

Hence, The equation of the line in the form of Ax + By = C is 3x - y = 7.

To know more about Linear equations click the link given below.

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Answer from: kinslou6506

$\boxed{3x - y = 5}}$

Step-by-step explanation:

The coordinates of the two points are (4, 7) and (3, 4).

(a) Calculate the slope of the line

$\begin{array}{rcl}m & = & \dfrac{y_{2} - y_{1}}{x_{2} - x_{1}}\\\\&= & \dfrac{7 - 4}{4 - 3}\\\\& = & \dfrac{3}{1}\\\\ & = &3\\\end{array}$

(b) Calculate the y-intercept

$\begin{array}{rcl}y & = & mx + b\\7 & = & 3 \times 4 + b\\7 & = & 12 + b\\b & = & -5\\\end{array}$

y = 3x - 5

This is the point-slope form of the equation.

(d) Convert to standard form

$\begin{array}{rcl}y & = & 3x - 5\\-3x + y & = & -5\\3x - y & = & -5\\\end{array}\\\text{The standard form of the equation is }\boxed{\mathbf{3x- y = -5}}$

Answer from: Quest

solution:

we have to construct

∠m nt ≅ ∠p qr

the steps to draw this construction are

step 1: use a compass to draw an arc from point q which intersects the side pq at point a and the side qr at point b.

step 2: draw a segment nt and use the same width of the compass to draw an arc from point n which intersects the segment nt at a point x.

step 3:

step 4: join points n and y using a straightedge.

step 3:

option (d).maintaining the same width of the compass as ab, draw an arc from point x such that it intersects the arc drawn from n in a point y.

to draw congruent angles , 1. width of compasses while drawing two angles should be same i.e from point at which angle has to be drawn, 2.the distance between the two points where the compass intersects the two sides should be same while drawing any two congruent angles.

Answer from: Quest

b). 4320 have a nice day

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