Me with my math (image attached is the problem)!

C. p + q = b and D. p . q = c. The two  true statements about p and q for a quadratic trinomial of the form x² + bx + c that can be factored as (x + p)(x + q) is p + q = b and p . q = c.

The easiest way to solve this problem is developing the product (x + p)(x + q) to a trinomial quadratic form.

(x + p)(x + q) = x² + qx + px + p.q = x² + (p + q)x + p.q

The equation above has the form x² + bx + c from which we can deduce the coefficients of x² + (p + q)x + p.q as follow:

a = 1, b = p + q, and c = p . q

a

step-by-step explanation: