Aset of data is normally distributed with a mean of 64 and a standard deviation of 2.5. what percent of the data is in the interval 64-66.5?

34.13%

Step-by-step explanation:

We know that the mean is:

And the standard deviation is:

The probability that a randomly selected X data is between 64 and 66.5 is:

Now we calculate the Z-score

For X = 64 the Z-score is:

For X = 66.5 the Z-score is:

Looking in the normal table we have to:

The percentage is:

where are the options?

step-by-step explanation:

step-by-step explanation:

here's what happens:

1) the graph of f   = x^2 is shifted 2 units to the right.

2) the resulting graph is reflected in the x-axis, so that the parabola now opens down.

3) this final result is transformed up by 5 units.