Given: δabc is an isosceles triangle where ab = bc. prove: m∠bac = m∠bca proof: statement reason 1. let δabc be an isosceles triangle where ab = bc. given 2. create point d on so that bisects ∠abc as shown. constructing an angle bisector 3. m∠abd = m∠dbc definition of angle bisector 4. bd = bd 5. δabd ≅ δcbd sas 6. m∠bac = m∠bca corresponding angles of congruent triangles are equal. what is the reason for statement 4 in this proof? a. transitive property of equality b. definition of midpoint c. definition of parallel lines d. reflexive property of equality

c. y = 1/4 x + 5

step-by-step explanation:

first, put the equation of the line on the graph into slope-intercept form

(y = mx + b):   y = -4x + 8

second, a perpendicular line has to have "an opposite/reciprocal slope" to the original slope. so, find the "m" value in your original equation (it's -4, right? )

original slope: m = -4   perpendicular slope: change the sign to its opposite and find the reciprocal ("flip" the number)

new slope is now positive (b/c the original slope was negative 4), and it's 1/4 (not the original slope of 4 or 4/1)

is there a picture

step-by-step explanation:

answer: your correct answer is b. d.

step-by-step explanation:

the graph is negative for all real values of x where   -6 < x < -2.

step-by-step explanation:

this refers to the values of f(x) in the area below the x-axis.