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Mathematics, 27.06.2019 06:00 bella6786

Find exact solution of  \cos( {2x - \frac{\pi}{2} })^{2} = 1 - \sin(2x - \frac{\pi}{2} ) for 0 \leqslant x \leqslant 3\pi

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Find exact solution of [tex] \cos( {2x - \frac{\pi}{2} })^{2} = 1 - \sin(2x - \frac{\pi}{2} ) [/tex]...
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