An arrow is shot slightly upwards from the top of a 60-feet tall hill. the arrow stays in the air for 6 seconds before hitting the ground. the height of the arrow in feet, t seconds after it is shot, is modeled by the graph below. the domain represents the arrow's . the range of this function is [, ]. for this function, the range represents the arrow's .

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.

answer

step-by-step explanation:

are ya tryin to ask something or is this a statement

answer: -10

step-by-step explanation:

s(t) = 1 - 10t

s(x) = 1 - 10x

s(x + h) = 1 - 10(x + h)

            = 1 - 10x - 10h

s(x + h) - s(x) = 1 - 10x - 10h - (1 - 10x)

                      = 1 - 10x - 10h - 1 + 10x

                      = -10h

= -10