Mathematics, 26.06.2019 16:50 danny5598
What is the solution of log((3x + 4))4096 = 4? ( the 3x+4 is like an exponent but lower
Answers: 1
![\bf \textit{exponential form of a logarithm} \\\\ \log_a b=y \implies a^y= b\qquad\qquad a^y= b\implies \log_a b=y \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \log_{3x+4}(4096)=4\implies \stackrel{\textit{exponential form}}{(3x+4)^4=4096}\implies (3x+4)^4=2^{12} \\\\\\ \stackrel{~\hfill \textit{same exponents, the bases must be the same}}{(3x+4)^4=2^{3\cdot 4}\implies (3x+4)^4=(2^3)^4}\implies 3x+4=2^3\implies 3x+4=8 \\\\\\ 3x=4\implies x=\cfrac{4}{3}](/tpl/images/0020/1708/916ca.png)
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What is the solution of log((3x + 4))4096 = 4? ( the 3x+4 is like an exponent but lower...
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