In the rhombus abcd, angle dae = 30. if eb is 6 cm what is the length of da

Required Basic Knowledge.

Rhombus is a parallelogram with equal sides.

i.e.

diagonals bisect eachother. (DE=EB),(AE=EC) &(AED = DEC = CEB = BEA =90°)

And

AD=DC=CB=BA

SOLUTION

——————

Cosider ∆ADE;

AED =90° (refer above details)

given. DAE=30°

DE=6cm (DE=EB; also refer above)

To find:length of AD

Taking Cosine of Angle A

Cos(A) =DE/AD

->Cos(30°) =6cm/(AD)

->(√3/2) = 6cm/(AD)

-> AD =6÷(√3/2) cm

->AD =6×(2/√3) cm

->AD =12/√3 cm (;√3=1.73 .approximately)

->DA=12/1.73 cm

-> DA = 6.936 cm (approx.)

Hope it helps...

Regards,

Leukonov/Olegion.

4.6875 pounds

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