The length of a rectangle is 5 inches longer than the width. the perimeter of the rectangle is 40 inches. what is the width of the rectangle, in inches?

W = 7.5 in

Step-by-step explanation:

We'll use the formula for the perimeter of a rectangle:  P = 2W + 2L.

Here, L = W + 5, so P = 2W + 2L becomes:

P = 2W + 2(W + 5), and this equals 40 in.

Thus we have the equation in W (the desired variable) as follows:

2W + 2(W + 5) = 40 in, or 4W + 10 = 40.

Then 4W = 30, and W = 7.5 in.

Based on the perimeter of this rectangle, the width is 7.5 inches.

The perimeter of a rectangle is calculated by:

= Length + Width + Length + Width

Assuming the width is denoted by x, the length would be:

Length = 5 + Width

Length = 5 + x

The perimeter is given so we can solve for the width:

Length + Width + Length + Width  = Perimeter

5 + x + x + 5 + x + x = 40

10 + 4x = 40

4x = 40 - 10

x = 30/4

x = 7.5 inches

In conclusion, the width is 7.5 inches.

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x = 25

step-by-step explanation:

a^2+b^2=c^2

7^2+24^2=c^2

49+576=625

sqrt625=25

x=25

i believe the answer is d.

hope it you! : d