The two dot plots below compare the forearm lengths of two groups of schoolchildren: two dot plots are shown one below the other. the title for the top dot plot is forearm length, group x and the title for the bottom plot is forearm length, group y. below the line for each dot plot is written length in inches. there are markings from 10 to 13 on each line at intervals of one. for the top line there are 4 dots above the first mark, 4 dots above the second mark, and 2 dots above the third mark. for the bottom line there are 2 dots above the second mark, 2 dots above the third mark, and 6 dots above the fourth mark. based on the visual inspection of the dot plots, which group appears to have the longer average forearm length? group x, because no child in the group has a forearm length longer than 12 inches. group x, because four children in the group have the least forearm length of 10 inches. group y, because a child in the group has the least forearm length of 10 inches. group y, because six children have a forearm length longer than 12 inches.

answer: 1000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000

step-by-step explanation:

the answer is: d) o, f, and kr.

atomic radius of bromine (br) is 114 pm.

atomic radius of oxygen (o) is 73 pm.

atomic radius of fluorine (f) is 72 pm.

atomic radius of krypron (kr) is 112 pm.

the atomic radius of a chemical element is a measure of the size of its atom.

the atomic radius varies with increasing atomic number, but usually increases because of increasing of number of electrons.

the atomic radius decreases across the periods because an increasing number of protons, because greater attraction between the protons and electrons.

chiken

step-by-step explanation:

answer is 8x+24

area of vanessa's patio = length × width

given, length = (3x² + 5x + 10)

width = (x² - 3x - 1)

area of vanessa's patio = (3x² + 5x + 10)(x² - 3x - 1)

= 3x²(x² - 3x - 1) + 5x(x² - 3x - 1) + 10(x² - 3x - 1)

= 3x⁴ - 9x³ - 3x² + 5x³ - 15x² - 5x + 10x² - 30x - 10

= 3x⁴ - 4x³ - 8x² - 35x - 10

hence, expression of vanessa's patio = (3x⁴ - 4x³ - 8x² - 35x - 10)