Is the work shown in the simplification below correct? explain. csc(t) sec(t) = 1 cos(t) ÷ 1 sin(t) = 1 cos(t) • sin(t) 1 = 1 sin(t) = tan(t)?

E2020

No, the simplification is not correct.

Cosecant is the reciprocal of sine, not cosine.

Secant is the reciprocal of cosine, not sine.

The given expression simplifies to cot(t).

The work shown in the simplification below is incorrect.

Step-by-step explanation:

To start; we have to know  what csc(t) and sec(t) is.

csc(t) = 1/sin(t)      and    sec(t)= 1/cos(t)

So in the above simplification it was all mixed up, csc(t) was substituted with 1/cos(t) instead of 1/sin(t) and sec(t) was substituted with 1/sin(t) instead of 1/cos(t).

So, we are going to solve it the right way;

csc(t) sec(t) =   ÷  

                   =     ×  

                    =

                    = cot(t)

Therefore csc(t) sec(t) = cot(t)   and not tan(t).

relating to or denoting a system of numbers and arithmetic based on the number ten, tenth parts, and powers of ten.

it alot will look like this 4.4

i think it might be a but you might want a second opinion