Find f’(x). 1. f(x)=x^2-5x+1 2. f(x)=10/x

1) 2x-5                 2)  -10/x^2

Step-by-step explanation:

Use power rule and constant rule for the first one:

1) f(x)=x^2-5x^1+1                                (x^n)'=nx^(n-1) and (c)'=0

f'(x)=2x^1-5(1)x^0+0                        

f'(x)=2x-5(1)                                        x^0=1

f'(x)=2x-5

Use just power rule for last one after a rewrite

2) f(x)=10/x

f(x)=10x^(-1) now use power rule

f'(x)=-10x^(-2) =-10/x^2

y=sec x is the correct answer

~batmans wife dun dun

multiplication is multiplication.   it might feel harder depending on what level of math you are in, but generally it will be the same old stuff, while implementing some new concepts and methods of solving work.