Acombination lock like the one shown below has threedials. each of the dials has numbers ranging from 1 to 25. ifrepeated numbers are allowed, how many differentcombinations are possible with the lock?

15625

Step-by-step explanation:

Let us consider each dial individually.

We have 25 choices for the first dial.

We then have 25 choices for the second dial.

We then have 25 choices for the third dial.

Let us consider any particular combination, the probability that combination is right is (probability the first number is right) * (probability the second number is right) * (probability the third number is right) = 1/25 * 1/25 * 1/25 = 1/15625

Therefore there are 15625 combinations

see attached

step-by-step explanation:

given the function as;

write the equation replacing f(x) with y

form   and fill a table containing values of y with corresponding values of x

you can take a range for   values of x as -3≤x≤3

solving for x=-3

for x=-2

repeat the same procedure to get the values of y for the remaining ,x=-1 to x=3

plot the values of y against values   of x and obtain the following graph