∆abc is reflected about the line y = -x to give ∆a'b'c with verticesa'(-1, 1), b'(-2, -1), c(-1,0). what are the vertices of ∆abc? options: a. a(1, -1), b(-1, -2). c(0, -1)b. a(-1, 1), b(1, 2), c(0, 1)c. a(-1,-1), b(-2, -1), c(-1,0)d. a(1, 1), b(2, -1), c(1,0)e. a(1, 2), b(-1, 1), c(0, 1)edit: it's b i figured it out

add the table and i will answer correctly

step-by-step explanation:

b. 6

step-by-step explanation:

we are given the table representing an exponential function.

we can see from the table that, as x is increasing, the value of y is increasing in the power of 6.

i.e. the following relation is obtained,

x = 1, y = 6

x = 2, y = 36 =

x = 3, y = 216 =

x = 4, y = 1296 =

x = 5, y = 7776 =

so, the geometric series obtained is .

thus, the common ratio is given by = = 6.

hence, the common ratio is 6.