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Mathematics, 25.06.2019 14:00 mya1318

Tanx= sinx/cosx. therefore, tan(90-a)= . (all angle measurements are in degrees.) 1/tan(90-a) 1/sin a 1/cos(90-a) 1/tan a

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Tanx= sinx/cosx. therefore, tan(90-a)= . (all angle measurements are in degrees.) 1/tan(90-a) 1/sin...
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