Solve the system of equations y=2x-3 y=x^2-2x-8

Step-by-step explanation:

(a) Set the two functions equal to each other

(b) Factor the quadratic equation

Find two numbers that multiply to give -5 and add to give ₄9.

Possible pairs are 1, -5; -1, 5;

By trial and error, you will find that 1 and -5 work:

1 × (-5) = -5 and 1 - 5= -4

x² - 4x - 8 = (x + 1)(x - 5)

(c) Solve the quadratic

all but the second one

step-by-step explanation:

cuz that one goes over 180

mark brainliest

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