Every evening jenna empties her pockects and puts her change in a jar. one week she had 38 coins, all of them dimes and quarters. when she added them up she had a total of 6.95every evening jenna empties her pockects and puts her change in a jar. one week she had 38 coins, all of them dimes and quarters. when she added them up she had a total of 6.95

17 dimes, 21 quarters

Step-by-step explanation:

I suppose you want to know how many dimes and quarters she had in her jar.

Let's say x = dimes and y = quarters.

We can make the following 2 equations:

1) x + y = 38 (number of coins in the jar)

2) 10x + 25y = 695 (a number of dimes plus a number of quarters sum up to 695 cents)

From 1), we can isolate y: y = 38 - x, and place that value in the second equation:

10x + 25y = 695

10x + 25 (38 - x) = 695

10x + 950 - 25x = 695, then we subtract 950 on both sides and simplify

-15x = -255

x = 17

So, Jenna had 17 dimes.

y = 38 - x, so y = 38 - 17 = 21

And she had 21 quarters.

e^-kt = n/n0 = 0.79  

-kt = ln 0.79  

t = - ln 0.79/0.0001  

= 2357 years

step-by-step explanation:

step-by-step explanation: