Which is an equation of a circle with center ( -5, -7) that passes through the point ( 0, 0 )

(x+5)^2+(y+7)^2=74

Step-by-step explanation:

So we are given this (x+5)^2+(y+7)^2=r^2

We need to find r so just plug in your point (0,0) for (x,y) and solve for r :)

(0+5)^2+(0+7)^2=r^2

25+49=r^2

74=r^2

So the answer is (x+5)^2+(y+7)^2=74

37/3

step-by-step explanation:

step 1: simplify both sides of the equation.

7x+8(x+

1

4

)=3(6x−9)−8

7x+(8)(x)+(8)(

1

4

)=(3)(6x)+(3)(−9)+−8(distribute)

7x+8x+2=18x+−27+−8

(7x+8x)+(2)=(18x)+(−27+−8)(combine like terms)

15x+2=18x+−35

15x+2=18x−35

tep 2: subtract 18x from both sides.

15x+2−18x=18x−35−18x

−3x+2=−35

step 3: subtract 2 from both sides.

−3x+2−2=−35−2

−3x=−37

step 4: divide both sides by -3.

−3x

−3

=

−37

−3

x=

37

3

whaere is the picture

step-by-step explanation: