Find the probability that a randomly selected passenger has a waiting time greater than 3.25 minutes

0.6389

Step-by-step explanation:

This question is on a rectangle distribution

We apply; Area × probability

9× height = 1 unit squarefind the height of the rectangle

h=1/9

The waiting time greater than 3.25  will be = 9-3.25= 5.75

P(time> 3.25 minutes) = 5.75 × 1/9 = 0.6389

correct answer is infinitely many solutions

step-by-step explanation:

2(2x + 3) = -4 + 2(2x + 5)

solving the above equation:

4x + 6 = -4 +4x +10

combining like terms

4x -4x = -4+10-6

0=0

since both sides are 0=0, we end up into true statement it means it has infinite many solutions.

so correct answer is infinitely many solutions

problem:

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

f(5/2) = 10/3

i hope this !