A2600-pound truck is stopped at a red light on a hill with an incline of 25°. ignoring the force of friction, what force is required to keep the truck from rolling down the hill? (show work)

  about 1099 pounds

Step-by-step explanation:

The weight of the truck is directed downward. It is countered by a force normal to the plane of the hill and one that is parallel to the plane of the hill. The question is asking about this latter force.

The magnitude of the force parallel to the hillside required to keep the truck stationary is ...

  (2600 lb)·sin(25°) ≈ 1098.81 lb ≈ 1099 lb

1.4

2.3

step-by-step explanation:

the formula for the constant of variation is

y= kx

divide each side by x

y/x =kx/x

y/x =k

we know a and y

1.   y/x = k

4/1 =4

check the other values to make sure they are the same

8/2 = 4   12/3 =4   and 16/4 =4  

the constant of variation is 4

2.   y/x = k

3/1 =3

check the other values to make sure they are the same

6/2 = 3   9/3 =3   and 12/4 =3  

the constant of variation is 3

in problems involving proportions, we can use cross products to test whether two ratios are equal and form a proportion. to find the cross products of a proportion, we multiply the outer terms, called the extremes, and the middle terms, called the means.

hope it