Given that the circles are congruent, can you conclude that ∠jkn is ≅ ∠gfh

Yes

Step-by-step explanation:

Think simple.

The picture has already provided us with the information that ∠EFT ≅ ∠LKM, and we also have:

∠EFT ≅ ∠GFH (opposite angles)

∠LKM ≅ ∠JKN (opposite angles as well)

Therefore ∠JKN ≅ ∠GFH

(n^3 - n)

= n(n-1)(n+1)

since it is divisible by 3 and 2 ,because it is a multiple 3 consecutive number

if, n-1 is odd then n+1 is also odd, then it is a multiple of 9

but if, n-1 is even then n+1 is also even, then it is a multiple of 4

so, largest multiple = max(9*2, 4*3) = max(18, 12) = 18