Acircle with a center at (5,-2) also has the point (8,2) that lies on the circle. what is the equation of the circle?

Step-by-step explanation:

You get the center just by reading the given point.

(x - 5)^2 + (x + 2)^2 = r^2 Notice that the center switches signs.

(8,2) is given so that you can figure out the radius.

The radius uses the distance formula to get from (5,-2) to (8,2)

x1 = 5

x2 = 8

y1 = -2

y2 = 2

formula

d^2 = (x1 - x2)^2 + (y1 - y2)^2

solution

d^2 = (5 - 8)^2 + (-2 - 2)^2

d^2 = (-3)^2 + (-4)^2

d^2 = 9 + 16

d^2 = 25

Answer

(x - 5)^2 + (y + 2)^2  =  25

b.an increase in a causes b to decrease

it's equivalent, so we can say that its equal.

let's call the denominator x and the numerador is 18 less then denominator, x - 18.

multiply

2.x = 5.(x - 18)

2x = 5x - 90

90 = 5x - 2x

90 = 3x

x = 90/3

x = 30

so: