Right triangle abc is on a coordinate plane. segment ab is on the line y = 2 and is 3 units long. point c is on the line x = −1. what is the y value of point c if the area of δabc is 6 units squared? 5 6 7 8

6

Step-by-step explanation

On the graph, the intersection point of horizontal line y=2 and vertical line x=-1 will be where point B is. Since AB is 3 units long, you'll want to count 3 spaces to the right, so A will be located at (2, 2). This is your base. Plug this into the formula for area of a triangle.

1/2base x height

1/2(3) x height= 6

1.5 x height= 6

6/1.5= 4

Height= 4

Count four spaces up from B, and you'll wind up on (-1, 6)

Hope this helps :)

6

Step-by-step explanation:

there are no answer choices

step-by-step explanation:

the equation of the parallel line would be y = 2x + 9

step-by-step explanation:

to start we need to find the slope of the original line. we can do that by looking at the coefficient of x, which is 2

since the slope of the original line is 2 and parallel lines have the same slope, we know the new line will also have 2 slope. now we can use that along with the point given in point-slope form to get the find equation.

y - y1 = m(x - x1)

y - 5 = 2(x + 2)

y - 5 = 2x + 4

y = 2x + 9