Solve for x in the equation y^2 + 2x + 1 = 17.

x = −1 ± √17

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B

Step-by-step explanation:

So your equation is actually x^2+2x+1=17

Left hand side is already set for rewriting it as a perfect square

So you have actually that (x+1)^2=17

Now you just take square root of both sides

x+1=(pm) sqrt(17)                        (pm) means plus or minus

x=-1 (pm) sqrt(17)                         I subtracted 1 on both sides

B

what are the options? ?

step-by-step explanation:

it would be 4 over -2 divided by -1 over 3.

if you want a solution it would be 4

you flip it so it would be 4/-2 divided by 3/-1 then it would be 12/3 and you would simplify it to 4