Suppose that there are two types of tickets to a show: advance and same-day. advance tickets cost $25 and same-day tickets cost $35. for one performance, there were 45 tickets sold in all, and the total amount paid for them was $1375 . how many tickets of each type were sold?

For this case we propose a system of equations:

x: Variable representing the anticipated tickets

y: Variable representing the same day tickets

So:

We clear x from the first equation:

We substitute in the second equation:

We look for the value of x:

Thus, 20 of anticipated type and 25 of same day type were sold.

20 of anticipated type and 25 of same day type were sold.

20 advance tickets and 25 same-day tickets.

Step-by-step explanation:

Set up a system of equations.

Let be "a" the number of advance tickets and "s" the number of same-day tickets.

Then:

You can use the Elimination method. Multiply the second equation by -25, then add both equations and solve for "s":

Substitute into an original equation and solve for "a":

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

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