Ashipping box in the shape of a cube has an edge length of 8 inches. it can hold 8 mugs with no extra space between them. if the dimensions of the shipping box are all doubled, what is the maximum number of mugs that the larger box can hold? 16 24 48 64

64

Step-by-step explanation:

Volume of a cube is:

V = s³

When s = 8 in:

V = (8 in)³ = 512 in³

When s is doubled (s = 16 in):

V = (16 in)³ = 4096 in³

Now we can write a proportion:

8 mugs / 512 in³ = x mugs / 4096 in³

x = 64

no solution

step-by-step explanation:

there is not enough information in the problem to solve.

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step-by-step explanation: