Acircular garden with a radius of 8 feet is surrounded by a circular path with a width of 3 feet. what is the approximate area of the path alone? use 3.14 for t. 172.70 ft? 178.98 ft? 200.96 it? 379.94 ft?

Option 2: 178.98 square feet

Step-by-step explanation:

The inner circular garden is surrounded by 3 feet wide path so in order to find the area of the path we have to calculate the area of inner circular garden and the area of garden with the outer wide path.

The radius of inner garden = r_1 = 8 feet

The radius of garden and path combined= r_2= 8+3= 11 feet

Area of inner garden: A_1:

A_1= πr_1^2

= 3.14 * (8)^2

=3.14 * 64

=200.96 square feet

Area of path and garden combined: A_2:

A_2= πr_2^2

= 3.14 * (11)^2

= 3.14 * 121

=379.94 square feet

In order to find the area of the path, we have to subtract the area of inner garden from the area of path and garden combined. That is:

A_2 - A_1

= 379.94 - 200.96

= 178.98 square feet

So the area of the path is 178.98 square feet. Hence, option 2 is the correct answer ..

the answer is 13 cm

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