Consider the sequence 130, 143, 156, 169, write an explicit formula to represent the arithmetic sequence and use it to find the 13th term.

a. a(n) = 130 + (n-1)13; 286

b. a(n) = 130 + 13n; 299

c. a(n) = 130 + 13n; 286

d. a(n) = 130 + (n-1)13; 299

A(n)=130+13(n-1) ; 86

Step-by-step explanation:

Here is the sequence

130,143,156,169

the first term denoted by a is 130 and the common difference denoted by d is second term minus first term

143 - 130 = 13

Hence a=130 and d = 13

Now we have to evaluate to 13th term.

The formula for nth term of any Arithmetic Sequence is

A(n) = a+(n-1)d

Hence substituting the values of a ,and d  get

A(n)=130+13(n-1)

To find the 13th term , put n = 13

A(13)=130+13*(13-1)

      = 130+13*12

      = 130+156

A(13) = 286

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step-by-step explanation:

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~courtney