How much would $400 be worth after 11 years, if it were invested at 4% interest compounded monthly? (use the formula below and round your answer to the nearest cent.)

The formula for compound interest is: A = P(1 +r/n)^nt

Where P is the principal ( starting value)

r is the interest rate

n is the number of compounds

and t is the number of years.

Fill in the letters with the given information:

A = 400(1+0.04/12)^(12*11)

A = 400(1.00333)^132

A = 400*1.551557

A = 620.63

The answer is $620.63

i found two solutions,   n = 2 • ± √3 = ± 3.4641

step-by-step explanation:

step-by-step explanation:

descending order means to order the polynomials from the term with the largest exponent to the term with the smallest exponent.  

therefore, the correct answer is d.