Janet can do a job in three hours while gary can do the same job in two hours. if janet works for an hour before gary be in her how long will it take them to finish the job together?

Janet = 1/3

Gary = 1/2

(1/3) + (1/2) = 5/6

Let x = time they both can do the job together

(1/2) + (5/6)x = 1

Solve for x to find your answer.

step-by-step explanation:

i love jeffery and believe there is truth in tati and james' answers

step-by-step explanation:

yes i have heard the tea

i believe both

no, tati didnt over exaggerate

james might might idk and tbh dont rly care