17. the colosseum in rome was the largest amphitheater built in the roman empire. the interior of the colosseum is a perfect circle. the roof of this enormous amphitheater was about 600 feet in diameter. if the center of the colosseum is assumed to be at origin, then write an equation for the circle that represents the roof of the colosseum.

Step-by-step explanation:

we know that

The equation of the circle (the roof of the Colosseum) in standard form is equal to

where

(h,k) is the center and r is the radius

we have

(h,k)=(0,0) ----> is the origin

----> the radius is half the diameter

substitute

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

cant

step-by-step explanation: there is no picture