Solve the system y-10=3x, 2y = 6x + 20

they are the same line! hence there are infinite number of solutions

Step-by-step explanation:

y-10=3x (rearrange)

we get:  y = 3x + 10 eq. (1)

2y=6x+20 (divide both sides by 2)

we get:  y = 3x + 10 eq. (2)

We can see that (1) = (2).

i.e they are the same line! hence there are infinite number of solutions.

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204