The sum of two numbers is 62.  their difference is 10.  what are the numbers?

let the 1st no. be x

let the second no. be y

so,ATQ

x+y=62 is the first equation

x-y=10

therefore by elimination method

x+y=62

x-y=10

2x+0=72

2x=72

x=72/2

x=36

therefore

x=36

and

y=from 2nd equation

x-y=10

36-y=10

-y=10-36

-y=-26

y=26

HOPE THIS HELPED

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b. x + 1

step-by-step explanation:

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